Alle tabellen doorzoeken met SQL

1 minute read

Een tijdje terug had ik iets nodig om een waarde in een tabel op te zoeken in een grote SQL Database. Uiteindelijk kwam ik op onderstaande stored procedure uit. Al wel enkele jaren oud, maar hij heeft me absoluut gered!

CREATE PROC SearchAllTables
(
	@SearchStr nvarchar(100)
)
AS
BEGIN

	-- Copyright © 2002 Narayana Vyas Kondreddi. All rights reserved.
	-- Purpose: To search all columns of all tables for a given search string
	-- Written by: Narayana Vyas Kondreddi
	-- Site: http://vyaskn.tripod.com
	-- Tested on: SQL Server 7.0 and SQL Server 2000
	-- Date modified: 28th July 2002 22:50 GMT


	CREATE TABLE #Results (ColumnName nvarchar(370), ColumnValue nvarchar(3630))

	SET NOCOUNT ON

	DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110)
	SET  @TableName = ''
	SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')

	WHILE @TableName IS NOT NULL
	BEGIN
		SET @ColumnName = ''
		SET @TableName = 
		(
			SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
			FROM 	INFORMATION_SCHEMA.TABLES
			WHERE 		TABLE_TYPE = 'BASE TABLE'
				AND	QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
				AND	OBJECTPROPERTY(
						OBJECT_ID(
							QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
							 ), 'IsMSShipped'
						       ) = 0
		)

		WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
		BEGIN
			SET @ColumnName =
			(
				SELECT MIN(QUOTENAME(COLUMN_NAME))
				FROM 	INFORMATION_SCHEMA.COLUMNS
				WHERE 		TABLE_SCHEMA	= PARSENAME(@TableName, 2)
					AND	TABLE_NAME	= PARSENAME(@TableName, 1)
					AND	DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar')
					AND	QUOTENAME(COLUMN_NAME) > @ColumnName
			)
	
			IF @ColumnName IS NOT NULL
			BEGIN
				INSERT INTO #Results
				EXEC
				(
					'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) 
					FROM ' + @TableName + ' (NOLOCK) ' +
					' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
				)
			END
		END	
	END

	SELECT ColumnName, ColumnValue FROM #Results
END

Updated: